7+42*3^(2-3a)=14*3^(2a)+7

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Solution for 7+42*3^(2-3a)=14*3^(2a)+7 equation:



7+42*3^(2-3a)=14*3^(2a)+7
We move all terms to the left:
7+42*3^(2-3a)-(14*3^(2a)+7)=0
We add all the numbers together, and all the variables
42*3^(-3a+2)-(14*3^2a+7)+7=0
Wy multiply elements
126a(--(14*3^2a+7)+7=0
We use the square of the difference formula
126a(+(14*3^2a+7)+7=0

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